(7x^2+9)(4x-7+5/x)

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Solution for (7x^2+9)(4x-7+5/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(7*x^2+9)*(4*x+5/x-7) = 0

(7*x^2+9)*(4*x+5*x^-1-7) = 0

4*x+5*x^-1-7 = 0

4*x^1+5*x^-1-7*x^0 = 0

(4*x^2-7*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-7*x^1+5*x^0) = 0

x^1

4*x^2-7*x+5 = 0

4*x^2-7*x+5 = 0

DELTA = (-7)^2-(4*4*5)

DELTA = -31

DELTA < 0

x in { } 

1 = 0

7*x^2+9 = 0

7*x^2 = -9 // : 7

x^2 = -9/7

x belongs to the empty set

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